25x^2+10x=8

Solution for 25x^2+10x=8 equation:

25x^2+10x=8

We move all terms to the left:

25x^2+10x-(8)=0

a = 25; b = 10; c = -8;
Δ = b2-4ac
Δ = 102-4·25·(-8)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*25}=\frac{-40}{50}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*25}=\frac{20}{50}
=2/5
$